Exercice 2

7.2 μs

0.007853981633974483

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begin
    Δh = 4.0
    P₀ = 1e5
    ρ = 1e3
    g = 9.81
    D = 0.1
    S = π * (D / 2) ^ 2
end

11.0 ms

$v = \sqrt{\frac{2 (P_{0} - ρ g Δ h)}{ρ}} .$

16.3 μs

11.023611023616535

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v = √(2(P₀ - ρ * g * Δh) / ρ)

8.7 μs

q̇ᵥ

0.08657923851956292

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q̇ᵥ = S * v

2.7 ms

Le débit maximal vaut donc :

${\dot{q}}_{v} = 86.6 L s^{- 1} .$

7.0 μs

$H = \frac{v^{2}}{2 g} = 6.19 m .$

4.3 μs

6.19367991845056

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H = v ^ 2 / 2 / g

26.4 μs